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1/5(3x+4)=1/2(4x+2)
We move all terms to the left:
1/5(3x+4)-(1/2(4x+2))=0
Domain of the equation: 5(3x+4)!=0
x∈R
Domain of the equation: 2(4x+2))!=0We calculate fractions
x∈R
(2x4/(5(3x+4)*2(4x+2)))+(-5x3/(5(3x+4)*2(4x+2)))=0
We calculate terms in parentheses: +(2x4/(5(3x+4)*2(4x+2))), so:
2x4/(5(3x+4)*2(4x+2))
We multiply all the terms by the denominator
2x4
We add all the numbers together, and all the variables
2x^4
We do not support expression: x^4
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