-(3x-3)+(2-x)=16

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Solution for -(3x-3)+(2-x)=16 equation: 



-(3x-3)+(2-x)=16

We move all terms to the left:

-(3x-3)+(2-x)-(16)=0

We add all the numbers together, and all the variables

-(3x-3)+(-1x+2)-16=0

We get rid of parentheses

-3x-1x+3+2-16=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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