1/5(30x+40)-5=-3/4(24x-32)

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Solution for 1/5(30x+40)-5=-3/4(24x-32) equation: 



1/5(30x+40)-5=-3/4(24x-32)

We move all terms to the left:

1/5(30x+40)-5-(-3/4(24x-32))=0



Domain of the equation: 5(30x+40)!=0

x∈R





Domain of the equation: 4(24x-32))!=0

x∈R



We calculate fractions


(4x2/(5(30x+40)*4(24x-32)))+(-(-15x3)/(5(30x+40)*4(24x-32)))-5=0



We calculate terms in parentheses: +(4x2/(5(30x+40)*4(24x-32))), so:

4x2/(5(30x+40)*4(24x-32))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-(-15x3)/(5(30x+40)*4(24x-32))), so:

-(-15x3)/(5(30x+40)*4(24x-32))

We add all the numbers together, and all the variables

-(-15x^3)/(5(30x+40)*4(24x-32))

We multiply all the terms by the denominator


-(-15x^3)

We do not support expression: x^3

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