12=9/5c+33

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Solution for 12=9/5c+33 equation: 



12=9/5c+33

We move all terms to the left:

12-(9/5c+33)=0



Domain of the equation: 5c+33)!=0

c∈R



We get rid of parentheses

-9/5c-33+12=0

We multiply all the terms by the denominator


-33*5c+12*5c-9=0

Wy multiply elements

-165c+60c-9=0

We add all the numbers together, and all the variables

-105c-9=0

We move all terms containing c to the left, all other terms to the right

-105c=9

c=9/-105

c=-3/35

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