1/5(25x-40)=5x+32

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Solution for 1/5(25x-40)=5x+32 equation: 



1/5(25x-40)=5x+32

We move all terms to the left:

1/5(25x-40)-(5x+32)=0



Domain of the equation: 5(25x-40)!=0

x∈R



We get rid of parentheses

1/5(25x-40)-5x-32=0

We multiply all the terms by the denominator


-5x*5(25x-40)-32*5(25x-40)+1=0

Wy multiply elements

-25x^2(2-160x(2+1=0

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