1/5(25-10b)+9=1/3(9b-30)-6

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Solution for 1/5(25-10b)+9=1/3(9b-30)-6 equation:



1/5(25-10b)+9=1/3(9b-30)-6
We move all terms to the left:
1/5(25-10b)+9-(1/3(9b-30)-6)=0
Domain of the equation: 5(25-10b)!=0
b∈R
Domain of the equation: 3(9b-30)-6)!=0
b∈R
We add all the numbers together, and all the variables
1/5(-10b+25)-(1/3(9b-30)-6)+9=0
We calculate fractions
(3b9/(5(-10b+25)*3(9b-30))+(-5b0/(5(-10b+25)*3(9b-30))+9=0
We can not solve this equation

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