40-5y+3=-2y-10-4y

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Solution for 40-5y+3=-2y-10-4y equation: 



40-5y+3=-2y-10-4y

We move all terms to the left:

40-5y+3-(-2y-10-4y)=0

We add all the numbers together, and all the variables

-5y-(-6y-10)+40+3=0

We add all the numbers together, and all the variables

-5y-(-6y-10)+43=0

We get rid of parentheses

-5y+6y+10+43=0

We add all the numbers together, and all the variables

y+53=0

We move all terms containing y to the left, all other terms to the right

y=-53

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