1/5(20x-35)=9

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Solution for 1/5(20x-35)=9 equation: 



1/5(20x-35)=9

We move all terms to the left:

1/5(20x-35)-(9)=0



Domain of the equation: 5(20x-35)!=0

x∈R



We multiply all the terms by the denominator


-9*5(20x-35)+1=0

Wy multiply elements

-45x(2+1=0

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