4(6+c)=32

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Solution for 4(6+c)=32 equation: 



4(6+c)=32

We move all terms to the left:

4(6+c)-(32)=0

We add all the numbers together, and all the variables

4(c+6)-32=0

We multiply parentheses

4c+24-32=0

We add all the numbers together, and all the variables

4c-8=0

We move all terms containing c to the left, all other terms to the right

4c=8

c=8/4

c=2

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