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1/5(2(x-1)+26)=x
We move all terms to the left:
1/5(2(x-1)+26)-(x)=0
Domain of the equation: 5(2(x-1)+26)!=0We add all the numbers together, and all the variables
x∈R
-1x+1/5(2(x-1)+26)=0
We multiply all the terms by the denominator
-1x*5(2(x-1)+26)+1=0
Wy multiply elements
-5x^2(2+1=0
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