-152=-4(4v+6)

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Solution for -152=-4(4v+6) equation: 



-152=-4(4v+6)

We move all terms to the left:

-152-(-4(4v+6))=0



We calculate terms in parentheses: -(-4(4v+6)), so:

-4(4v+6)

We multiply parentheses

-16v-24

Back to the equation:

-(-16v-24)



We get rid of parentheses

16v+24-152=0

We add all the numbers together, and all the variables

16v-128=0

We move all terms containing v to the left, all other terms to the right

16v=128

v=128/16

v=8

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