1/5(15c-10)=c+7

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Solution for 1/5(15c-10)=c+7 equation: 



1/5(15c-10)=c+7

We move all terms to the left:

1/5(15c-10)-(c+7)=0



Domain of the equation: 5(15c-10)!=0

c∈R



We get rid of parentheses

1/5(15c-10)-c-7=0

We multiply all the terms by the denominator


-c*5(15c-10)-7*5(15c-10)+1=0

Wy multiply elements

-5c^2(1-35c(1+1=0

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