(10y+5)-(3y+12)=105

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Solution for (10y+5)-(3y+12)=105 equation: 



(10y+5)-(3y+12)=105

We move all terms to the left:

(10y+5)-(3y+12)-(105)=0

We get rid of parentheses

10y-3y+5-12-105=0

We add all the numbers together, and all the variables

7y-112=0

We move all terms containing y to the left, all other terms to the right

7y=112

y=112/7

y=16

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