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1/5(10x-15)=1/2(6x-4)
We move all terms to the left:
1/5(10x-15)-(1/2(6x-4))=0
Domain of the equation: 5(10x-15)!=0
x∈R
Domain of the equation: 2(6x-4))!=0We calculate fractions
x∈R
(2x6/(5(10x-15)*2(6x-4)))+(-5x1/(5(10x-15)*2(6x-4)))=0
We calculate terms in parentheses: +(2x6/(5(10x-15)*2(6x-4))), so:
2x6/(5(10x-15)*2(6x-4))
We multiply all the terms by the denominator
2x6
We add all the numbers together, and all the variables
2x^6
We do not support expression: x^6
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