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1/3(24x-54)=11(x-4)+5
We move all terms to the left:
1/3(24x-54)-(11(x-4)+5)=0
Domain of the equation: 3(24x-54)!=0We multiply all the terms by the denominator
x∈R
-((11(x-4)+5))*3(24x-54)+1=0
We calculate terms in parentheses: -((11(x-4)+5))*3(24x-54), so:
(11(x-4)+5))*3(24x-54
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(11(x-4)+5))*3(24x-54
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