1/4x=7/2x-3

Solution for 1/4x=7/2x-3 equation:

1/4x=7/2x-3

We move all terms to the left:

1/4x-(7/2x-3)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x-3)!=0

x∈R


We get rid of parentheses

1/4x-7/2x+3=0

We calculate fractions


2x/8x^2+(-28x)/8x^2+3=0

We multiply all the terms by the denominator


2x+(-28x)+3*8x^2=0

Wy multiply elements

24x^2+2x+(-28x)=0

We get rid of parentheses

24x^2+2x-28x=0

We add all the numbers together, and all the variables

24x^2-26x=0

a = 24; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·24·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*24}=\frac{52}{48}
=1+1/12
$