7(z+4)=2(z-4)

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Solution for 7(z+4)=2(z-4) equation: 



7(z+4)=2(z-4)

We move all terms to the left:

7(z+4)-(2(z-4))=0

We multiply parentheses

7z-(2(z-4))+28=0



We calculate terms in parentheses: -(2(z-4)), so:

2(z-4)

We multiply parentheses

2z-8

Back to the equation:

-(2z-8)



We get rid of parentheses

7z-2z+8+28=0

We add all the numbers together, and all the variables

5z+36=0

We move all terms containing z to the left, all other terms to the right

5z=-36

z=-36/5

z=-7+1/5

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