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1/4x+1/8x+24=60
We move all terms to the left:
1/4x+1/8x+24-(60)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
1/4x+1/8x-36=0
We calculate fractions
8x/32x^2+4x/32x^2-36=0
We multiply all the terms by the denominator
8x+4x-36*32x^2=0
We add all the numbers together, and all the variables
12x-36*32x^2=0
Wy multiply elements
-1152x^2+12x=0
a = -1152; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-1152)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-1152}=\frac{-24}{-2304} =1/96 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-1152}=\frac{0}{-2304} =0 $
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