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5x+8=4x^2
We move all terms to the left:
5x+8-(4x^2)=0
determiningTheFunctionDomain -4x^2+5x+8=0
a = -4; b = 5; c = +8;
Δ = b2-4ac
Δ = 52-4·(-4)·8
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{17}}{2*-4}=\frac{-5-3\sqrt{17}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{17}}{2*-4}=\frac{-5+3\sqrt{17}}{-8} $
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