1/4*x-3=1/2*x+12

Solution for 1/4*x-3=1/2*x+12 equation:

1/4*x-3=1/2*x+12

We move all terms to the left:

1/4*x-3-(1/2*x+12)=0


Domain of the equation: 4*x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2*x+12)!=0

x∈R


We get rid of parentheses

1/4*x-1/2*x-12-3=0

We calculate fractions


(-4x^2)/16x^2+2x^2/16x^2-12-3=0

We add all the numbers together, and all the variables

(-4x^2)/16x^2+2x^2/16x^2-15=0

We multiply all the terms by the denominator


(-4x^2)+2x^2-15*16x^2=0

We add all the numbers together, and all the variables

2x^2+(-4x^2)-15*16x^2=0

Wy multiply elements

2x^2+(-4x^2)-240x^2=0

We get rid of parentheses

2x^2-4x^2-240x^2=0

We add all the numbers together, and all the variables

-242x^2=0

a = -242; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-242)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-484}=0$