3(x+1)-2(6x+3)=2(x-1)

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Solution for 3(x+1)-2(6x+3)=2(x-1) equation: 



3(x+1)-2(6x+3)=2(x-1)

We move all terms to the left:

3(x+1)-2(6x+3)-(2(x-1))=0

We multiply parentheses

3x-12x-(2(x-1))+3-6=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-9x-(2x-2)-3=0

We get rid of parentheses

-9x-2x+2-3=0

We add all the numbers together, and all the variables

-11x-1=0

We move all terms containing x to the left, all other terms to the right

-11x=1

x=1/-11

x=-1/11

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