1/4(x-8)+1/2(x+2)=x+3

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Solution for 1/4(x-8)+1/2(x+2)=x+3 equation: 



1/4(x-8)+1/2(x+2)=x+3

We move all terms to the left:

1/4(x-8)+1/2(x+2)-(x+3)=0



Domain of the equation: 4(x-8)!=0

x∈R





Domain of the equation: 2(x+2)!=0

x∈R



We get rid of parentheses

1/4(x-8)+1/2(x+2)-x-3=0

We calculate fractions


-x+(2xx/(4(x-8)*2(x+2))+(4xx/(4(x-8)*2(x+2))-3=0

We can not solve this equation

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