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4x(x+8)=5472
We move all terms to the left:
4x(x+8)-(5472)=0
We multiply parentheses
4x^2+32x-5472=0
a = 4; b = 32; c = -5472;
Δ = b2-4ac
Δ = 322-4·4·(-5472)
Δ = 88576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{88576}=\sqrt{256*346}=\sqrt{256}*\sqrt{346}=16\sqrt{346}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{346}}{2*4}=\frac{-32-16\sqrt{346}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{346}}{2*4}=\frac{-32+16\sqrt{346}}{8} $
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