1/4(x+6)+1/8x=1/2x(x+1)

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Solution for 1/4(x+6)+1/8x=1/2x(x+1) equation: 



1/4(x+6)+1/8x=1/2x(x+1)

We move all terms to the left:

1/4(x+6)+1/8x-(1/2x(x+1))=0



Domain of the equation: 4(x+6)!=0

x∈R





Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R





Domain of the equation: 2x(x+1))!=0

x∈R



We calculate fractions


32x^2/(4(x+6)*8x*2x(x+1)))+(8x^2x/(4(x+6)*8x*2x(x+1)))+(-(1*4(x+6)*8x)/(4(x+6)*8x*2x(x+1)))=0



We calculate terms in parentheses: -(1*4(x+6)*8x)/(4(x+6)*8x*2x(x+1))), so:

1*4(x+6)*8x)/(4(x+6)*8x*2x(x+1))

We multiply all the terms by the denominator


1*4(x+6)*8x)

Wy multiply elements

32x^2(x

Back to the equation:

-(32x^2(x)



We can not solve this equation

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