X-3(x-6)=2(x-3)+8

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Solution for X-3(x-6)=2(x-3)+8 equation: 



X-3(X-6)=2(X-3)+8

We move all terms to the left:

X-3(X-6)-(2(X-3)+8)=0

We multiply parentheses

X-3X-(2(X-3)+8)+18=0



We calculate terms in parentheses: -(2(X-3)+8), so:

2(X-3)+8

We multiply parentheses

2X-6+8

We add all the numbers together, and all the variables

2X+2

Back to the equation:

-(2X+2)



We add all the numbers together, and all the variables

-2X-(2X+2)+18=0

We get rid of parentheses

-2X-2X-2+18=0

We add all the numbers together, and all the variables

-4X+16=0

We move all terms containing X to the left, all other terms to the right

-4X=-16

X=-16/-4

X=+4

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