1/4(x+3)=7(x+1)

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Solution for 1/4(x+3)=7(x+1) equation:



1/4(x+3)=7(x+1)
We move all terms to the left:
1/4(x+3)-(7(x+1))=0
Domain of the equation: 4(x+3)!=0
x∈R
We multiply all the terms by the denominator
-((7(x+1)))*4(x+3)+1=0
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3
We calculate terms in parentheses: -((7(x+1)))*4(x+3), so:
(7(x+1)))*4(x+3

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