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3a+1/a=8
We move all terms to the left:
3a+1/a-(8)=0
Domain of the equation: a!=0We multiply all the terms by the denominator
a∈R
3a*a-8*a+1=0
We add all the numbers together, and all the variables
-8a+3a*a+1=0
Wy multiply elements
3a^2-8a+1=0
a = 3; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·3·1
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{13}}{2*3}=\frac{8-2\sqrt{13}}{6} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{13}}{2*3}=\frac{8+2\sqrt{13}}{6} $
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