1/4(x+1)=3(1-x)+1/2x

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Solution for 1/4(x+1)=3(1-x)+1/2x equation: 



1/4(x+1)=3(1-x)+1/2x

We move all terms to the left:

1/4(x+1)-(3(1-x)+1/2x)=0



Domain of the equation: 4(x+1)!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/4(x+1)-(3(-1x+1)+1/2x)=0

We calculate fractions


2x/(8x^2+4x)+(-(-3x+4xx)/(8x^2+4x)=0



We calculate terms in parentheses: +(-(-3x+4xx)/(8x^2+4x), so:

-(-3x+4xx)/(8x^2+4x

We multiply all the terms by the denominator


-(-3x+4xx)

We get rid of parentheses

3x-4xx

Back to the equation:

+(3x-4xx)



We add all the numbers together, and all the variables

2x/(8x^2+4x)+(+3x-4xx)=0

We get rid of parentheses

2x/(8x^2+4x)+3x-4xx=0

We multiply all the terms by the denominator


2x+3x*(8x^2+4x)-4xx*(8x^2+4x)=0

We multiply parentheses

24x^3+12x^2-32x^3-16x^2+2x=0

We do not support expression: x^3

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