3x-(3x(1+x)-2x)=3

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Solution for 3x-(3x(1+x)-2x)=3 equation: 



3x-(3x(1+x)-2x)=3

We move all terms to the left:

3x-(3x(1+x)-2x)-(3)=0

We add all the numbers together, and all the variables

3x-(3x(x+1)-2x)-3=0



We calculate terms in parentheses: -(3x(x+1)-2x), so:

3x(x+1)-2x

We add all the numbers together, and all the variables

-2x+3x(x+1)

We multiply parentheses

3x^2-2x+3x

We add all the numbers together, and all the variables

3x^2+x

Back to the equation:

-(3x^2+x)



We get rid of parentheses

-3x^2+3x-x-3=0

We add all the numbers together, and all the variables

-3x^2+2x-3=0

a = -3; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·(-3)·(-3)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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