1/4(k+4)=3/4(k-4)

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Solution for 1/4(k+4)=3/4(k-4) equation: 



1/4(k+4)=3/4(k-4)

We move all terms to the left:

1/4(k+4)-(3/4(k-4))=0



Domain of the equation: 4(k+4)!=0

k∈R





Domain of the equation: 4(k-4))!=0

k∈R



We calculate fractions


(4kk/(4(k+4)*4(k-4)))+(-12kk/(4(k+4)*4(k-4)))=0



We calculate terms in parentheses: +(4kk/(4(k+4)*4(k-4))), so:

4kk/(4(k+4)*4(k-4))

We multiply all the terms by the denominator


4kk

Back to the equation:

+(4kk)





We calculate terms in parentheses: +(-12kk/(4(k+4)*4(k-4))), so:

-12kk/(4(k+4)*4(k-4))

We multiply all the terms by the denominator


-12kk

Back to the equation:

+(-12kk)



We get rid of parentheses

4kk-12kk=0

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