1/4(g+8)=1/3(17-2g)

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Solution for 1/4(g+8)=1/3(17-2g) equation: 



1/4(g+8)=1/3(17-2g)

We move all terms to the left:

1/4(g+8)-(1/3(17-2g))=0



Domain of the equation: 4(g+8)!=0

g∈R





Domain of the equation: 3(17-2g))!=0

g∈R



We add all the numbers together, and all the variables

1/4(g+8)-(1/3(-2g+17))=0

We calculate fractions


(3g(-)/(4(g+8)*3(-2g+17)))+(-4gg/(4(g+8)*3(-2g+17)))=0



We calculate terms in parentheses: +(3g(-)/(4(g+8)*3(-2g+17))), so:

3g(-)/(4(g+8)*3(-2g+17))

We add all the numbers together, and all the variables

3g0/(4(g+8)*3(-2g+17))

We multiply all the terms by the denominator


3g0

We add all the numbers together, and all the variables

3g

Back to the equation:

+(3g)





We calculate terms in parentheses: +(-4gg/(4(g+8)*3(-2g+17))), so:

-4gg/(4(g+8)*3(-2g+17))

We multiply all the terms by the denominator


-4gg

Back to the equation:

+(-4gg)



We get rid of parentheses

3g-4gg=0

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