3(t-4)=-2(t+)+14

Solution for 3(t-4)=-2(t+)+14 equation:

3(t-4)=-2(t+)+14

We move all terms to the left:

3(t-4)-(-2(t+)+14)=0

We add all the numbers together, and all the variables

3(t-4)-(-2(+t)+14)=0

We multiply parentheses

3t-(-2(+t)+14)-12=0


We calculate terms in parentheses: -(-2(+t)+14), so:

-2(+t)+14

We multiply parentheses

-2t+14

Back to the equation:

-(-2t+14)


We get rid of parentheses

3t+2t-14-12=0

We add all the numbers together, and all the variables

5t-26=0

We move all terms containing t to the left, all other terms to the right

5t=26

t=26/5

t=5+1/5