1/4(8x-20)=1/3(3x-12)

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Solution for 1/4(8x-20)=1/3(3x-12) equation: 



1/4(8x-20)=1/3(3x-12)

We move all terms to the left:

1/4(8x-20)-(1/3(3x-12))=0



Domain of the equation: 4(8x-20)!=0

x∈R





Domain of the equation: 3(3x-12))!=0

x∈R



We calculate fractions


(3x3/(4(8x-20)*3(3x-12)))+(-4x8/(4(8x-20)*3(3x-12)))=0



We calculate terms in parentheses: +(3x3/(4(8x-20)*3(3x-12))), so:

3x3/(4(8x-20)*3(3x-12))

We multiply all the terms by the denominator


3x3

We add all the numbers together, and all the variables

3x^3

We do not support expression: x^3

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