1/4(8b-12)=17

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Solution for 1/4(8b-12)=17 equation: 



1/4(8b-12)=17

We move all terms to the left:

1/4(8b-12)-(17)=0



Domain of the equation: 4(8b-12)!=0

b∈R



We multiply all the terms by the denominator


-17*4(8b-12)+1=0

Wy multiply elements

-68b(8+1=0

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