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(x+10)(600/x-5)=600
We move all terms to the left:
(x+10)(600/x-5)-(600)=0
Domain of the equation: x-5)!=0We multiply parentheses ..
x∈R
(+600x^2-5x+6000x-50)-600=0
We get rid of parentheses
600x^2-5x+6000x-50-600=0
We add all the numbers together, and all the variables
600x^2+5995x-650=0
a = 600; b = 5995; c = -650;
Δ = b2-4ac
Δ = 59952-4·600·(-650)
Δ = 37500025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{37500025}=\sqrt{25*1500001}=\sqrt{25}*\sqrt{1500001}=5\sqrt{1500001}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5995)-5\sqrt{1500001}}{2*600}=\frac{-5995-5\sqrt{1500001}}{1200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5995)+5\sqrt{1500001}}{2*600}=\frac{-5995+5\sqrt{1500001}}{1200} $
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