1/4(32x+20)-4=-1/3(12x-18)

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Solution for 1/4(32x+20)-4=-1/3(12x-18) equation: 



1/4(32x+20)-4=-1/3(12x-18)

We move all terms to the left:

1/4(32x+20)-4-(-1/3(12x-18))=0



Domain of the equation: 4(32x+20)!=0

x∈R





Domain of the equation: 3(12x-18))!=0

x∈R



We calculate fractions


(3x1/(4(32x+20)*3(12x-18)))+(-(-4x3)/(4(32x+20)*3(12x-18)))-4=0



We calculate terms in parentheses: +(3x1/(4(32x+20)*3(12x-18))), so:

3x1/(4(32x+20)*3(12x-18))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-4x3)/(4(32x+20)*3(12x-18))), so:

-(-4x3)/(4(32x+20)*3(12x-18))

We add all the numbers together, and all the variables

-(-4x^3)/(4(32x+20)*3(12x-18))

We multiply all the terms by the denominator


-(-4x^3)

We do not support expression: x^3

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