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5(x+3)=3x-(5-x)
We move all terms to the left:
5(x+3)-(3x-(5-x))=0
We add all the numbers together, and all the variables
5(x+3)-(3x-(-1x+5))=0
We multiply parentheses
5x-(3x-(-1x+5))+15=0
We calculate terms in parentheses: -(3x-(-1x+5)), so:We get rid of parentheses
3x-(-1x+5)
We get rid of parentheses
3x+1x-5
We add all the numbers together, and all the variables
4x-5
Back to the equation:
-(4x-5)
5x-4x+5+15=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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