1/4(24+48)=1/3(-18n-36)

Solution for 1/4(24+48)=1/3(-18n-36) equation:

1/4(24+48)=1/3(-18n-36)

We move all terms to the left:

1/4(24+48)-(1/3(-18n-36))=0


Domain of the equation: 3(-18n-36))!=0

n∈R


We add all the numbers together, and all the variables

-(1/3(-18n-36))+1/472=0

We calculate fractions


()/(-25488n)+(3n(-)/(-25488n)=0


We calculate terms in parentheses: +(3n(-)/(-25488n), so:

3n(-)/(-25488n

We add all the numbers together, and all the variables

3n0/(-25488n

We multiply all the terms by the denominator


3n0

We add all the numbers together, and all the variables

3n

Back to the equation:

+(3n)


We add all the numbers together, and all the variables

3n+()/(-25488n)=0

We multiply all the terms by the denominator


3n*(-25488n)+()=0

We add all the numbers together, and all the variables

3n*(-25488n)=0

We multiply parentheses

-76464n^2=0

a = -76464; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-76464)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-152928}=0$