3x+4(4x-5)=8(2x-4)

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Solution for 3x+4(4x-5)=8(2x-4) equation: 



3x+4(4x-5)=8(2x-4)

We move all terms to the left:

3x+4(4x-5)-(8(2x-4))=0

We multiply parentheses

3x+16x-(8(2x-4))-20=0



We calculate terms in parentheses: -(8(2x-4)), so:

8(2x-4)

We multiply parentheses

16x-32

Back to the equation:

-(16x-32)



We add all the numbers together, and all the variables

19x-(16x-32)-20=0

We get rid of parentheses

19x-16x+32-20=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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