1/3y+(-18)=2

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Solution for 1/3y+(-18)=2 equation: 



1/3y+(-18)=2

We move all terms to the left:

1/3y+(-18)-(2)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



determiningTheFunctionDomain
1/3y-2+(-18)=0

We add all the numbers together, and all the variables

1/3y-20=0

We multiply all the terms by the denominator


-20*3y+1=0

Wy multiply elements

-60y+1=0

We move all terms containing y to the left, all other terms to the right

-60y=-1

y=-1/-60

y=1/60

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