4(x+1)+7=5(2x-3))+7

Solution for 4(x+1)+7=5(2x-3))+7 equation:

4(x+1)+7=5(2x-3))+7

We move all terms to the left:

4(x+1)+7-(5(2x-3))+7)=0

We add all the numbers together, and all the variables

4(x+1)-(5(2x-3))=0

We multiply parentheses

4x-(5(2x-3))+4=0


We calculate terms in parentheses: -(5(2x-3)), so:

5(2x-3)

We multiply parentheses

10x-15

Back to the equation:

-(10x-15)


We get rid of parentheses

4x-10x+15+4=0

We add all the numbers together, and all the variables

-6x+19=0

We move all terms containing x to the left, all other terms to the right

-6x=-19

x=-19/-6

x=3+1/6