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1/3x=3x-6
We move all terms to the left:
1/3x-(3x-6)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-3x+6=0
We multiply all the terms by the denominator
-3x*3x+6*3x+1=0
Wy multiply elements
-9x^2+18x+1=0
a = -9; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·(-9)·1
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{10}}{2*-9}=\frac{-18-6\sqrt{10}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{10}}{2*-9}=\frac{-18+6\sqrt{10}}{-18} $
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