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1/3x=3x-56
We move all terms to the left:
1/3x-(3x-56)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-3x+56=0
We multiply all the terms by the denominator
-3x*3x+56*3x+1=0
Wy multiply elements
-9x^2+168x+1=0
a = -9; b = 168; c = +1;
Δ = b2-4ac
Δ = 1682-4·(-9)·1
Δ = 28260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28260}=\sqrt{36*785}=\sqrt{36}*\sqrt{785}=6\sqrt{785}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-6\sqrt{785}}{2*-9}=\frac{-168-6\sqrt{785}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+6\sqrt{785}}{2*-9}=\frac{-168+6\sqrt{785}}{-18} $
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