1/3x=3x+10

Solution for 1/3x=3x+10 equation:

1/3x=3x+10

We move all terms to the left:

1/3x-(3x+10)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-3x-10=0

We multiply all the terms by the denominator


-3x*3x-10*3x+1=0

Wy multiply elements

-9x^2-30x+1=0

a = -9; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·(-9)·1
Δ = 936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{936}=\sqrt{36*26}=\sqrt{36}*\sqrt{26}=6\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{26}}{2*-9}=\frac{30-6\sqrt{26}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{26}}{2*-9}=\frac{30+6\sqrt{26}}{-18}
$