(3x+2)+2x+(2x+2)+(4x-18)=90

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Solution for (3x+2)+2x+(2x+2)+(4x-18)=90 equation: 



(3x+2)+2x+(2x+2)+(4x-18)=90

We move all terms to the left:

(3x+2)+2x+(2x+2)+(4x-18)-(90)=0

We add all the numbers together, and all the variables

2x+(3x+2)+(2x+2)+(4x-18)-90=0

We get rid of parentheses

2x+3x+2x+4x+2+2-18-90=0

We add all the numbers together, and all the variables

11x-104=0

We move all terms containing x to the left, all other terms to the right

11x=104

x=104/11

x=9+5/11

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