1/3x+9=7(2x-7)-13x

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Solution for 1/3x+9=7(2x-7)-13x equation: 



1/3x+9=7(2x-7)-13x

We move all terms to the left:

1/3x+9-(7(2x-7)-13x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We multiply all the terms by the denominator


-((7(2x-7)-13x))*3x+9*3x+1=0

Wy multiply elements

-((7(2x-7)-13x))*3x+27x+1=0

We add all the numbers together, and all the variables

27x-((7(2x-7)-13x))*3x+1=0

We move all terms containing x to the left, all other terms to the right

27x-((7(2x-7)-13x))*3x=-1

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