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1/3x+7=1/2(x+1
We move all terms to the left:
1/3x+7-(1/2(x+1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2(x+1)+7!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
2(x+1)!=-7
x∈R
(2x(x+7)/(6x^2(x+7)+(-(1*3x)/(6x^2(x+7)=0
We calculate terms in parentheses: +(2x(x+7)/(6x^2(x+7)+(-(1*3x)/(6x^2(x+7), so:
2x(x+7)/(6x^2(x+7)+(-(1*3x)/(6x^2(x+7
We can not solve this equation
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