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3(2+x)=-2(x+5)-4
We move all terms to the left:
3(2+x)-(-2(x+5)-4)=0
We add all the numbers together, and all the variables
3(x+2)-(-2(x+5)-4)=0
We multiply parentheses
3x-(-2(x+5)-4)+6=0
We calculate terms in parentheses: -(-2(x+5)-4), so:We get rid of parentheses
-2(x+5)-4
We multiply parentheses
-2x-10-4
We add all the numbers together, and all the variables
-2x-14
Back to the equation:
-(-2x-14)
3x+2x+14+6=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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