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1/3x+5=3/4x-2
We move all terms to the left:
1/3x+5-(3/4x-2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x-2)!=0We get rid of parentheses
x∈R
1/3x-3/4x+2+5=0
We calculate fractions
4x/12x^2+(-9x)/12x^2+2+5=0
We add all the numbers together, and all the variables
4x/12x^2+(-9x)/12x^2+7=0
We multiply all the terms by the denominator
4x+(-9x)+7*12x^2=0
Wy multiply elements
84x^2+4x+(-9x)=0
We get rid of parentheses
84x^2+4x-9x=0
We add all the numbers together, and all the variables
84x^2-5x=0
a = 84; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·84·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*84}=\frac{0}{168} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*84}=\frac{10}{168} =5/84 $
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