0.008(2-k)+0.03(k-2)=1

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Solution for 0.008(2-k)+0.03(k-2)=1 equation: 



0.008(2-k)+0.03(k-2)=1

We move all terms to the left:

0.008(2-k)+0.03(k-2)-(1)=0

We add all the numbers together, and all the variables

0.008(-1k+2)+0.03(k-2)-1=0

We multiply parentheses

-0.008k+0.03k+0.016-0.06-1=0

We add all the numbers together, and all the variables

0.022k-1.044=0

We move all terms containing k to the left, all other terms to the right

0.022k=1.044

k=1.044/0.022

k=47+0.01/0.022

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